Please help quickly

Figure J does not show y as a function of x ⇒ D

Step-by-step explanation:

y is a function of x if and only if every x has only one value of y

Let us check each given figure if it shows a function or not

#Figure F

∵ Every value of x has an arrow is pointed to one value of y

∴ Every x has only one value of y

∴ The figure shows y as a function of x

#Figure G

∵ The ordered pairs have different values of x-coordinates

∴ Every x-coordinate has only one value of y-coordinate

∴ The figure shows y as a function of x

#Figure H

∵ Every x in the table appears once

∴ Every x has only one value of y

∴ The figure shows y as a function of x

#Figure J

∵ The ordered pairs were drawn in the figure are (-3, -2), (-3, -3), (-2, 0),

  (-2, -1), (-1, 1), (-1, 2), (0, 3), (0, 4)

∵ x = -3 has two values of y, y = -2 and -3

∵ x = -2 has two values of y, y = 0 and -1

∵ x = -1 has two values of y, y = 1 and 2

∵ x = 0 has two values of y, y = 3 and 4

∴ Every x-coordinate has more than one value of y-coordinate

∴ Figure J does not show y as a function of x

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

this answer is !