the area of a trapezium is 594 sq. cm. The lengths of its parallel sides are in the ratio 4 : 5. The height of the trapezium is 12 cm. Find the lengths of the parallel sides.

1st side=44 cm, 2nd side= 55cm

Step-by-step explanation:

let a = '4x' , b = '5x'

h= 12cm

Area of trapezium=1/2*(a+b)h

area=594=1/2*9x*12

594*2/12=9x

594/6=9x

99=9x

99/9=11=x

therefore, 4x=4*11=44cm

             &5x=5*11=55cm

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.