Find the x- and y-intercepts of the line that passes through ( 3, -8) and ( -4, 13).

x-intercept = 1/3, y-intercept = 1

Step-by-step explanation:

y = mx + b (general equation where m=gradient, b=constant)

-8 = 3m + b (from first pair of coordinates)

13 = -4m + b (from second pair of coordinates)

3m + b - (-4m + b) = -8 - 13

7m = -21

m = -3

Using one of the linear equations above:

-8 = 3(-3) + b

-8 = -9 + b

b = 1

Therefore, the linear equation is: y = -3x + 1

To find x-intercept:

Let y = 0

0 = -3x + 1

-1 = -3x

x = 1/3

To find y-intercept:

Let x = 0

y = -3(0) + 1

y = 1

Therefore the x-intercept = 1/3 and y-intercept = 1 for the line that passes through (3, -8) and (-4, 13)

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)