Mathematics
Mathematics, 19.11.2020 08:00, 10040813

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Mathematics, 21.06.2019 13:10, mmaglaya1
Determine whether triangle tjd is congruent to triangle sek  givent (-4,-2), j (0,5), d (1,-1), s (-1,3), e (3,10), k (4,4)and explain the reason.  select one: a. yes, by sssb. no, by aasc. no, by asad. yes, by sas
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Mathematics, 21.06.2019 22:30, citiboy45
5, 6, 10 question: a. determine whether the side lengths form a triangle. (explain your reasoning) b. if it is a triangle, determine whether it is a right, acute, or obtuse triangle. (show your work)
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Mathematics, 22.06.2019 02:00, Zaxx2974
Part a what is the area of triangle i? show your calculation. part b triangles i and ii are congruent (of the same size and shape). what is the total area of triangles i and ii? show your calculation. part c what is the area of rectangle i? show your calculation. part d what is the area of rectangle ii? show your calculation. part e rectangles i and iii have the same size and shape. what is the total area of rectangles i and iii? show your calculation. part f what is the total area of all the rectangles? show your calculation. part g what areas do you need to know to find the surface area of the prism? part h what is the surface area of the prism? show your calculation. part i read this statement: “if you multiply the area of one rectangle in the figure by 3, you’ll get the total area of the rectangles.” is this statement true or false? why? part j read this statement: “if you multiply the area of one triangle in the figure by 2, you’ll get the total area of the triangles.” is this statement true or false? why?
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Mathematics, 22.06.2019 03:00, jshhs
You coordinate volunteers for litter cleanup in local parks. your spreadsheet lists drivers and the number of seat belts in each driver’s car. the spreadsheet calculates the number of drivers (d) and the total number of seat belts (s). you want to know the maximum number of volunteers, besides drivers, that can be transported to the park in a single trip given that each person must have a seat belt of their own.
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