In ΔJKL, \overline{JL} JL
is extended through point L to point M, \text{m}\angle LJK = (2x+2)^{\circ}m∠LJK=(2x+2)
∘
, \text{m}\angle KLM = (8x-16)^{\circ}m∠KLM=(8x−16)
∘
, and \text{m}\angle JKL = (3x+6)^{\circ}m∠JKL=(3x+6)
∘
. Find \text{m}\angle KLM. m∠KLM.

9514 1404 393

  48°

Step-by-step explanation:

Exterior angle KLM is equal to the sum of the remote interior angles.

  ∠KLM = ∠LJK + ∠JKL

  (8x -16)° = (2x +2)° +(3x +6)°

  8x -16 = 5x +8 . . . . . . . . . . divide by °, collect terms

  3x = 24 . . . . . . . . . . add 16-5x

  x = 8 . . . . . . . . divide by 3

The measure of the angle of interest is ...

  ∠KLM = (8x-16)° = (8·8 -16)°

  ∠KLM = 48°

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

answer is 33

step-by-step explanation: