Mathematics
Mathematics, 04.02.2020 11:45, jmcd10

How do i solve 4(3-y)=6-2(1-3y) ? i'm getting y= -4
12-4y=6-2-6y
12-4y=4-6y
12+2y=4
2y= -8
y= -4

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How do i solve 4(3-y)=6-2(1-3y) ? i'm getting y= -4
12-4y=6-2-6y
12-4y=4-6y
12+2y=...

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