Suppose the quantity x of super titan radial tires made available each week in the marketplace is related to the unit-selling price by the following equation where x is measured in units of a thousand and p is in dollars.
p-(1)/(2)x^(2)=48
how fast is the weekly supply of super titan radial tires being introduced into the marketplace when x = 9, p = 88.5, and the price/tire is decreasing at the rate of $4/week? (round your answer to the nearest whole number.)

Given condition:

p – [(1/2) x^2] = 48 (1)

By taking differentiation of equation (1); dp/dt represents the decreasing rate of change in the tire price and dx/dt represents rate of change of the tires being introduced.

x = 9

p = 88.5

Tire price decreasing rate = dp/dt = 4$ per week

Solution:

Differentiation is performed implicitly.

dp/dt – [(1/2) d(x^2)/dt ]= d(48) /dt

Putting value of dp/dt;

–  4 – [(1/2) * 2 x (dx/dt)] = 0

Where “– “is due to decreasing rate of change of tires price and derivate of a constant “48” is equal to “0”

x dx/dt = -4

dx/dt = -4/x

Where x = 9

So dx/dt = -4/9

Hence the tire supply rate is decreasing the at rate of -4/9. 

yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36