April invests $30,000, part at 6.5% annual interest and the balance at 4.2% annual interest. How much is invested at each rate if April receives a 1-year interest payment of $1662.50?

$17500 at 6.5% and $12500 at 4.2%

Step-by-step explanation:

Given

Let x be the amount invested at 6.5%Then (30000 - x) is invested at 4.2%

The equation for the interest:

x*6.5/100 + (30000 - x)*4.2/100 = 1662.500.065x + 1260 - 0.042x = 1662.500.023x = 1662.50 - 12600.023x = 402.5x = 402.5/0.023x = 17500

So $17500 invested at 6.5% and $12500 at 4.2%

Think of it as five or above give it a shove. change the 5 or above to the right to a zero and add one to the number on the left.

The correct answer is -3.9> -4.5 gucci playa