Catherine is at the Supermarket, and knows that she is 50 yards from her school. The map on her phone shows that the school is \large \frac{3}{4} inch from her current location. If Catherine's current location is 3 inches from home on the same map, how far is Catherine from her home? a 112.5 yards b 200 yards c 250.5 yards d 150 yards

b 200 yards

Step-by-step explanation:

Scaling

Real magnitudes can be scaled up or down to adapt to the size of a sheet of paper or the screen of a computer or phone.

Catherine knows she is 50 yards from the school and it's shown as a distance of 3/4 inch on her phone map.

We can calculate the scaling factor from the real distance to the map distance by dividing:

Now she sees that she's 3 inches from home on the same map. This is equivalent to a real distance of:

Catherine is 200 yards from her home.

b 200 yards

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92