Three Algebra 1 students are comparing how fast their social media posts have spread. Their results are shown in the following table. Write an exponential function to represent the spread of Ben's social media post.

Write an exponential function to represent the spread of Carter's social media post.

Graph each function using at least three points for each curve. All graphs should be placed together on the same coordinate plane, so be sure to label each curve. You may graph your equation by hand on a piece of paper and scan your work or you may use graphing technology.

Using the functions for each student, predict how many shares each student's post will be received on Day 3 and then on Day 10. Justify your answers.

If Amber decides to mail copies of her photo to the 45 residents of her grandmother's assisted living facility, the new function representing her photo shares is f(x) = 3(4)x + 45.

How does this graph compare with the original graph of Amber's photo share?

Based on your results, which students' post travels the fastest?
How is this shown in the equation form of the functions?

If you had to choose, would you prefer a post with fewer friends initially but more shares, like Amber, or more friends initially but fewer shares? Justify your answer with your calculations from previous questions.

IF YOU ANSWER ALL, I WILL GIVE YOU 75 PTS!!!

Which of the following best describes the purpose of the Committees of Correspondence?

A.It was to train express riders.

B.It was to share news among the colonies.

C.It was to keep in touch with Britain

D.It was to unite the colonies in friendship.

Step-by-step explanation:

my wifi is bad but i think the answer is

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.