Find y-intercept for 9x-5y=0.

y=-9/5x+0  the y intercept would simply be 0

Step-by-step explanation:

y=0

Step-by-step explanation:

9x-5y=0

9(0)-5y=0

-5y=0

-5y/-5=0/-5

y=0 (y intercept)

9x-5y=0

9x-5(0)= 0

9x=0

9x/9=0/9

x=0 (x intercept)

Hope this Helps :)

Have a good day :)

attachment?

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.