Mathematics, 18.11.2020 17:50, jason1702
Given that a bag of M & Ms has 21 brown candies, 15 orange candies, 10 yellow candies, 14 red candies, and 5 green candies, find the following probabilities. Enter all answers as reduced fraction. Do not use any spaces in your answers.
What is the probability of choosing a green M & M, eating it, and then choosing a brown M & M?
P( Answer
B | G
)= Answer
What is the probability of choosing a red M & M on the second try given that the first M & M was red and it was eaten?
Answers: 3
Mathematics, 21.06.2019 19:30, lalaokawami0912
Finally, the arena decides to offer advertising space on the jerseys of the arena’s own amateur volley ball team. the arena wants the probability of being shortlisted to be 0.14. what is this as a percentage and a fraction? what is the probability of not being shortlisted? give your answer as a decimal. those shortlisted are entered into a final game of chance. there are six balls in a bag (2 blue balls, 2 green balls and 2 golden balls). to win, a company needs to take out two golden balls. the first ball is not replaced. what is the probability of any company winning advertising space on their volley ball team jerseys?
Answers: 3
Given that a bag of M & Ms has 21 brown candies, 15 orange candies, 10 yellow candies, 14 red ca...
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