Given SD HT; SH=ST prove SHD= STD

The proof of is given below.

Given, SD is perpendicular to HT.

We have to prove .

Now, In ,

( since SD perpendicular to HT, so both will be 90 ).

( given in question ).

( common side in both the triangle ).

So, by Right angle hypotenuse congruence rule,

.

Hence the proved above.

For more details follow the link:

link

Δ SHD ≅ Δ STD (By SAS)

Step-by-step explanation:

Given:

SD⊥HT

SH=ST

Prove:

Δ SHD ≅ Δ STD

Computation:

SH=ST (Given)

SD = SD (Common)

∠SHD = ∠SDT (right angle) (SD⊥HT)

So,

Δ SHD ≅ Δ STD (By SAS)

the correct is answer is a 9-sided polygon!

66.666666667%

step-by-step explanation:

divide 150 by 100

divide 100 by 1.5

there you go!

decreased by 33.333333334%