What is the angle of depression from the start of a 6-foot high access ramp that ends at a point 40 feet away along the ground? Nearest tenth of a degree.

Step-by-step explanation:

The set up will give a right angles triangle;

Given

The height of the ramp (opposite) = 6 foot

distance away along the ground = 40 feet (adjacent)

Required

Angle of depression theta

Using the TOA identity;

tan theta = opposite/adjacent

tan theta = 6/40

tan theta = 0.15

theta = tan^-1{0.15}

theta =8.53 degrees

hence the angle of depression to nearest tenth of a degree is 89.5 degrees

1/800 is the right answer

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.