In a survey of 468 registered voters, 152 of them wished to see Mayor Waffleskate lose her next election. The Waffleskate campaign claims that no more than 32% of registered voters wish to see her defeated. Does the 95% confidence interval for the proportion support this claim? a. The reasonableness of the claim cannot be determined.
b. Yes
c. No

b. Yes

Step-by-step explanation: Confidence Interval for a population proportion is calculated as:

p ±

where

p is the sample proportion

n is sample size

z is z-score, in this case, as it is 95%, z-score=1.96

Calculating confidence interval:

p = 0.3248

0.3248 ±

0.3248 ±

0.3248 ± 0.0425

Interval: 0.2823 < μ < 0.3673

The interval means we are 95% sure the true mean is between 0.2823 and 0.3673. As the campaign claims a proportion of no more than 0.32 of the voters wants to see Mayor Waffleskate defeated and the number is in the confidence interval, the claim is supported.

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

21/58.

hope to be marked brainliest