Taking into account identical letters, how many ways can the researcher arrange the word CALLITRICHIDAE that start or end with vowels?

241,920 different ways

Step-by-step explanation:

We have 6 vowels, but A repeats twice and I repeats three times, so the number of ways in which each can either start or end the word:

³P₂ = 3! / (3 - 2)! = 6 / 1 = 6 ways

You can start words with A, E or I, or end the words with A, E, or I.

the remaining 8 consonants can be arranged in 8! ways = 40,320 ways

total number of ways that the letters can be arranged = 6 x 40,320 = 241,920 different ways

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation:

the answer is 1030 it's very simple math.