The mean June midday temperature in Desertville is 36°C and the standard deviation is 3°C. Assuming this data is normally distributed, how many days in June would you expect the midday temperature to be between 39°C and 42°C?

The value is  

Step-by-step explanation:

From the question we are told that

   The mean is  

    The standard deviation

Generally the probability that in June , the midday  temperature is between  

39°C and 42°C is mathematically represented as

=>  

From the z table  the area under the normal curve to the left corresponding to  1 and  2  is

     P(Z   < 2)  = 0.97725

and

    P(Z   < 1)  = 0.84134

=>  

Generally number of days in June would you expect the midday temperature to be between 39°C and 42°C

Here n is the number of days in June which is  n = 30

=>    

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )