What is the center and radius of the circle with the given equation?

(- 1, - 4 ) and r = 5

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

To obtain this form from the given equation use the method of completing the square.

Given

x² + y² + 2x + 8y = 8 ( rearrange by collecting x and y terms )

x² + 2x + y² + 8y = 8

To complete the square

add ( half the coefficients of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(4)x + 16 = 8 + 1 + 16

(x + 1)² + (y + 4)² = 25 ← in standard form

with centre (h, k ) = (- 1, - 4 ) and r = = 5

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc

what was there favorite food