PLEASE HELP! (STATS) A box contains 10 batteries of which 6 are still working. Jada starts picking batteries one at a time without replacement from the box and testing them to see if they work. Find the probability that all of the first 3 she chooses will work? Group of answer choices

0.120

0.167

0.600

0.216

0.037

0.167

Step-by-step explanation:

Given: Total batteries = 10

Batteries that are still working = 6

Number of ways to pick 3 working batteries =

Number of ways of pick 3 batteries out of 10 =

Required probability =

Hence, the probability that all of the first 3 she chooses will work = 0.167

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

answer: 2530

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