TWO PART QUESTION Emilio throws a marshmallow into the air from his balcony. The height of the marshmallow (in feet) is represented by the equation h= -16(t-1/4)^2+49, where T is the time (in seconds) after he throws the marshmallow. What is the maximum height of the marshmallow?

SECOND PART

Emilio throws a marshmallow into the air from his balcony. The height of the marshmallow (in feet) is represented by the equation h= -16(t-1/4)^2+49, where T is the time (in seconds) after he throws the marshmallow. How long after Emilio throws the marshmallow does it reach its maximum height?

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point

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step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet