![y = 2x^2 - 4x + 5\\\\y = 2(x^2 - 2x) + 5\\\\y=2(\underline{x^2-2\cdot x\cdot1+1^2}-1^2)+5\\\\y=2\big[(x-1)^2-1\big]+5\\\\y=2(x-1)^2-2+5\\\\y=2(x-1)^2+3\quad\implies\quad vertex:\ (1\,,\ 3)](/tpl/images/0907/3005/41e27.png)
Find the vertex for the following equation.
y = 2x^2 - 4x + 5...
Mathematics, 18.11.2020 02:00, Tyrant4life
Find the vertex for the following equation.
y = 2x^2 - 4x + 5
Answers: 1
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