I need help to answer please

m∠N = 41°

Step-by-step explanation:

Here,

In △MNO, m∠M = (6x + 1°) ...(1)

m∠N = (3x - 10°) ...(2)

m∠0 = (x + 19°) ...(3)

Here, We know that the sum of all angles of a triangle is 180°

Then,

(6x + 1°) + (3x - 10°) + (x + 19°) = 180°

6x + 1° + 3x - 10° + x + 19° = 180°

6x + 3x + x + 1° - 10° + 19° = 180°

10x + 10° = 180°

10x = 180° - 10°

10x = 170°

x = 170° ÷ 10°

x = 17°

Now, put the value of x in (1), (2) and (3)

m∠M = (6x + 1°)

= (6(17) + 1°)

= (102° + 1°)

m∠M = 103°

m∠N = (3x - 10°)

= (3(17) - 10°)

= (51° - 10°)

m∠N = 41°

m∠0 = (x + 19°)

= (17 + 19°)

m∠0 = 36°

Thus, The m∠N = 41°

(6x + 1°) + (3x - 10°) + (x + 19°) = 180°

(6(17) + 1°) + (3(17) - 10°) + (17 + 19°) = 180°

103° + 41° + 36° = 180°

180° = 180°

Hence, L.H.S = R.H.S

-TheUnknownScientist

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