Michael is building a fence around his garden to keep the rabbits out. The perimeter of his garden is 42 feet. If the length of the garden is 5 more than the width, what are the dimensions of the fence? Hint: draw a rectangle, and label all 4 sides for the length and width, given what you know. *Show your work on paper!

a.) Write an equation to represent the situation.

b.) Solve your equation WITH units - you need to find the length AND the width.

a)

perimeter = 42 feet

let the width = y

let the length = 5+y

( the length is 5+y because it is 5 more than the width )

2(5+y)+2y=42

b)

2(5+y)+2y=42

10+2y+2y=42

4y=32

y=8

width = y

= 8

length = 5+y

= 5+8

= 13

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).