Your buddy constructs an angle bisector BD−→− for ∠ABC. She says that m∡ABD and m∡DBC formed by the angle bisector are congruent. Do you think that is always, sometimes or never true for angle bisectors?

Always true

Step-by-step explanation:

The definition of an interior or internal angle bisector is the the dividing line segment that splits the angle into two  equal angles (parts)

Therefore, given that the segment BD is the bisector of ∠ABC, then the formed angles m∡ABD and m∡DBC are, by definition of bisected ∠ABC, always congruent

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13