Write an equation of the line passing through point P that is perpendicular to the given line. P(6, 10), y = -3x + 13

y = 1/3x + 8

Step-by-step explanation:

*perpendicular means the reciprocal slope of the given line

m = 1/3

y = 1/3x + b

*plug in points with the point-slope equation

10 = 1/3(6) + b

10 = 2 + b

b = 8

*now plug everything into the equation

y = 1/3x + 8

y = 1/3x + 8

Step-by-step explanation:

1. Find slope of y = -3x+13

(m = -3)

2. Compute slope for perpendicular line

(m = 1/3)

basically, to find the perpendicular slope, you swap the numerator and denominator of your slope and swap it from negative to positive. (If you started with a positive slope it would turn negative)

3. Find the line with slope m=1/3 that passes through (6,0)

(y = 1/3x + 8)

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.