A waterfall has a height of 1700 feet. A pebble is thrown upward from the top of the falls with an initial velocity of  feet per second. The height of the pebble h in feet after t seconds is given by the equation h=-16t^2+24t+1700 . How long after the pebble is thrown will it hit the ground? PLEASE HEL

Step-by-step explanation:

The expression is given as:

Required

Determine how long it will hit the ground

When the pebble is on the ground, this implies that h = 0

So, we have that:

becomes

Reorder

Multiply through by -1

Solve using quadratic formula :

Where

So, we have:

or

or

or

But time can't be negative.

So:

Hence, it will take 11.085 seconds to hit the ground

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is