Find the equation of the line that passes through the points (4,1) and (-4, -5) A. y = 4x + 1
B. y = -4x - 5
C. y = 3/4 x -2
D. y = -3/4 x + 2

First, we must find the slope of the line using slope formula*.

Second, we now find the y-intercept, or b, using slope-intercept form, the slope we found, and one of the given points.

Lastly, we can now create the equation of the line.

The equation of the line that goes through the given points is C.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.