Write the cubic polynomial function f(x)in expanded form with zeros −6, −4,and −1,given that f(−2)=−32.

Step-by-step explanation:

Polynomials

It's possible to build a polynomial function by knowing its zeros and leading coefficient.

Given the zeros of a third-degree polynomial: x=x1, x=x2, and x=x3, the function is:

Where a is the leading coefficient.

We are given the zeros -6, -4, and -1, thus:

The value of a can be calculated by substituting the point (-2,-32):

Calculating:

Dividing by -8:

a = 4.

The polynomial is now complete:

Operating:

answer: sine

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?