![y = -5x - 3](/tpl/images/0901/4503/ea542.png)
Step-by-step explanation:
The data in the question are not properly presented.
See attachment for graph
To determine the graph, first we need to calculate the slope (m)
![m = \frac{y_2 - y_1}{x_2 - x_1}](/tpl/images/0901/4503/8ed0b.png)
Where x and y are corresponding values:
When x = -1; y = 2;
This implies ![(x_1,y_1) = (-1,2)](/tpl/images/0901/4503/96c1e.png)
When x = 0; y = -3
This implies ![(x_2,y_2) = (0,-3)](/tpl/images/0901/4503/91844.png)
So:
![m = \frac{y_2 - y_1}{x_2 - x_1}](/tpl/images/0901/4503/8ed0b.png)
![m = \frac{-3 - 2}{0 - (-1)}](/tpl/images/0901/4503/3673a.png)
![m = \frac{-3 - 2}{0 +1}](/tpl/images/0901/4503/3d382.png)
![m = \frac{-5}{1}](/tpl/images/0901/4503/a6376.png)
![m = -5](/tpl/images/0901/4503/dd21d.png)
The equation is then calculated using:
![y - y_1 = m(x-x_1)](/tpl/images/0901/4503/f6552.png)
Where:
![m = -5](/tpl/images/0901/4503/dd21d.png)
![(x_1,y_1) = (-1,2)](/tpl/images/0901/4503/96c1e.png)
![y - 2 = -5(x -(-1))](/tpl/images/0901/4503/cd5c7.png)
![y - 2 = -5(x +1)](/tpl/images/0901/4503/8feb9.png)
![y - 2 = -5x -5](/tpl/images/0901/4503/1871e.png)
Make y the subject
![y = -5x - 5 +2](/tpl/images/0901/4503/05090.png)
![y = -5x - 3](/tpl/images/0901/4503/ea542.png)
Please note that the graph I attached may/may not be the right graph to your question.
However, if you follow the steps I used in answering this question, you'll get the right answer to your question.
![Identify the function shown in this graph.
-5 -4 -3 -2 -1
2 3 4 5
O A. y = -5x - 3
B. y = 5x - 3
O](/tpl/images/0901/4503/996d4.jpg)