How many ways can we choose three items at random without replacement from five items (A, B, C, D, E) if the order of the selected items is not important? a) 60
b) 120
c) 10
d) 24

10

Step-by-step explanation:

This is a combination problem.

Given the set of items S = (A, B, C, D, E)

Total number of items in the set = 5

Amount to select is 3 items

This can be done in 5C3 number of ways

5C3 = 5!/(5-3)!3!

5C3 = 5!/2!3!

5C3 = 5*4*3!/2*3!

5C3 = 5*4/2

5C3 = 20/2

5C3 = 10

Hence this can be done in 10 ways if orders are not important

wth is with the little mtn top and what are you talking about like fix your words and accually make sence with them and i like was in a completly different question like three times like it seems like your ilitteret

ιт ιѕ (9χ^5+10)(81χ^10-90χ^5+100)

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ уσυ συт тσ∂α