100 POINTS Suppose ܶTU is on a coordinate plane located at T(-6,-2) and U(2,-6) Under a dilation of scale factor 1/4, TU becomes T'U' with coordinates T'(-3/2,-1/2) and U'(1/2,-3/2) Where is the center of the dilation located ? A(0,0)
B(2,2)
C(4,0)
D(4,4)

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

dont think so

step-by-step explanation:

irrational, cannot

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true