Heights were measured for a random sample of 10 plants grown while being treated with a particular nutrient. The sample mean and sample standard deviation of those height measurements were 46 centimeters and 7 centimeters, respectively. Assume that the population of heights of treated plants is normally distributed with mean μ. Based on the sample, can it be concluded that μ is different from 45 centimeters? Use the 0.05 level of significance.

The calculated value   t = 0.452< 2.2621 at 0.05 level of significance

null hypothesis is accepted

Based on the sample, can it be concluded that μ is not different from 45 centimeters

Step-by-step explanation:

Step( i ):-

Heights were measured for a random sample of 10 plants

Size of the sample 'n' = 10

Mean of the sample (x⁻ ) = 46 centimeters

Standard deviation of the sample (s) = 7 centimeters

Mean of the Population ( μ ) = 45

Step(ii):-

Null Hypothesis :H₀:( μ ) = 45

Alternative Hypothesis : H₁:  μ ) ≠ 45

Test statistic

           t = 0.452

  Degrees of freedom

                 γ = n-1 = 10 -1 = 9

t₀.₀₅ =  2.2621

The calculated value   t = 0.452< 2.2621 at 0.05 level of significance

null hypothesis is accepted

Based on the sample, can it be concluded that μ is not different from 45 centimeters

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

answer: your correct answer is b. d.

step-by-step explanation: