A rectangular field is 90 yards long and 60 yards wide. Give the length and width of another rectangular field that has the same perimeter but a larger area.

The length and width of another rectangular field with same perimeter but a larger area is 80 m by 70 m

Step-by-step explanation:

The perimeter of the existing field is

2(l + b)

= 2(90 + 60) = 2(150) = 300 yards

So we want another field having the same perimeter but a larger area

The area we have here is 90 * 60 = 5,400 square yards

If we had 80 by 70

Perimeter will still be 2(70 + 80) = 150

But the area will be 80 * 70 = 5,600 square yards

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2