Describe each of the following transformation that maps the figures described below. Be specific by naming lines of reflection, centers of rotation and degrees of rotation, distance and direction of translations, and centers of dilation with a scale factor. Determine if the transformation is a rigid transformation or a similarity transformation. Explain all reasoning. Part A: Figure 1 →Figure 4
Part B: Figure 2 → Figure 5

Part A: Figure 1 → Figure 4

Rigid Transformation

Equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin which are types of rigid transformation

Part B: Figure 2 → Figure 5

Similarity transformation

Figure 5 is Figure 2 dilated by a scale factor of 1/2, which is a form of a similarity transformation

Step-by-step explanation:

Part A: Figure 1 → Figure 4

The coordinates of the vertices of the preimage are;

(5, 10), (2, 4), (9, 2)

The coordinates of the vertices of the image are;

(-9, -2), (-2, -4), (-5, -10)

Which is equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin

Part B: Figure 2 → Figure 5

The coordinate points of figure 2 are;

(-9, 2), (-5, 10), and (-2, 4)

The coordinate points of figure 5 are;

(1, 2), (2.5, -1), and (4.5, 3)

The lengths of the sides of figure 2 are;

√((10 - 2)² + ((-5) - (-9))²) = 4·√5

√((10 - 4)² + ((-5) - (-2))²) = 3·√5

√((2 - 4)² + ((-9) - (-2))²) = √53

The lengths of the sides of figure 5 are;

√(((-1) - 2)² + (2.5 - 1)²) = (3·√5)/2

√((4.5 - 2.5)² + (3 - (-1))²) = 2·√5

√((4.5 - 1)² + (3 - 2)²) = (√53)/2

Therefore. Figure 5 is Figure 2 dilated by a scale factor of 1/2

Therefore, given that the sides of Figure 2 and Figure 5 are rotated by 180°

We have;

Figure 5 is obtained as follows;

1) The rotation of figure 2 by 180°, clockwise or anticlockwise about the origin to get;

(-9, 2), (-5, 10), and (-2, 4) → (9, -2), (5, -10), and (2, -4)

2) The image is translated left by 1 blocks and up by 6 blocks as follows;

(9, -2), (5, -10), and (2, -4)  → (8, 4), (4, -4), and (1, 2)

3) The image is then dilated by a scale factor of 1/2  with a center of dilation of (1, 2) to get;

Preimage (8, 4), (4, -4), and (1, 2) → Image (1, 2), (2.5, -1), and (4.5, 3).

what are the statements

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.