The expression \dfrac12bh 2 1 bhstart fraction, 1, divided by, 2, end fraction, b, h gives the area of a triangle where bbb is the base of the triangle and hhh is the height of the triangle. What is the area of a triangle with a base of 7 \text{ cm}7 cm7, start text, space, c, m, end text and a height of 4 \text{ cm}4 cm4, start text, space, c, m, end text?

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the answer is d on edge

step-by-step explanation:

answer:

idk

step-by-step explanation: