Mathematics, 16.11.2020 09:50, ilovejustinbieber42
The fourth term of a geometric progression is 4 and the seventh term is 32/125. Find the first term, the common ratio and the sum of the first nth terms. Hence, deduce the sum to infinity.
Answers: 1
![\frac{a_7}{a_4} =\frac{8}{125} =\frac{a_1\,r^6}{a_1\,r^3} =r^3\\then\\r=\sqrt[3]{\frac{8}{125} } =\frac{2}{5}](/tpl/images/0900/4888/c8ed4.png)
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The fourth term of a geometric progression is 4 and the seventh term is 32/125. Find the first term,...
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