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Solve by graphing

The lines do NOT intercept, then there is NO SOLUTION to the system

Step-by-step explanation:

Notice that the two lines given have the SAME slope (-3/2) and different y-intercepts. Therefore, when we graph them we are going to obtain two parallel lines (lines of the SAME slope) crossing the y-axis at different points.

We use for the first line two points like: (0, -1) and (2, -4)

and for the second line, the points (0, 3) and (2, 0)

The lines are plotted in the attached image.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

29.5977692753

step-by-step explanation: