The value of R. P. Mugs can be represented by the equation below, where x is the number of months after January 2001 and V is the value. If we wanted to find the minimum value V(x) will reach, what key feature would we be finding? DO NOT SOLVE v(x)=x^2-6x+13

The minimum value of V(x)  = 4

Step-by-step explanation:

Step(i) :-

Given equation  V(x) = x² - 6 x + 13  ...(i)

Differentiating equation (i) with respective to 'x' , we get

          V¹ (x) = 2 x - 6 ...(ii)

          2 x - 6 =0

          2 x = 6

           x = 3

Step(ii):-

Again Differentiating with respective to 'x' , we get

      V¹¹(x) = 2 > 0

v(x)=x^2-6x+13

put x =3

The minimum value of V(x) = 9 - 18+13 = 4

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5