Enter the number of complex zeros for the polynomial function in the box. f(x)=x3−96x2+400

The complex zeros of the polynomials  are 20i and -20i

Given the polynomials, the zeros of the polynomial are gotten by equating the function to zero and then factorizing as shown:

f(x)=x^3−96x^2+400

x^3−96x^2+400 = 0

x^2(x-96) + 400 = 0

x^2(x - 96) = -400

x^2 = -400

Get the required complex roots:

x^2 = -400

x = ±√-400

x = ±20i

Hence the complex zeros of the polynomials  are 20i and -20i

Learn more on zeros of polynomials here: link

step-by-step explanation:

answer: the answer is 40.82

step-by-step explanation: 3.14 x 13(or half of 26) to the power of 2