A toy rocket is launched vertically upward from a 12 foot platform with an initial velocity of 128 feet per second. Its height h at timet seconds after
launch is given by the equation h(t) = -16t2 + 128t + 12. How many
seconds until the rocket is 40 feet?

step-by-step explanation:

step by step solution :

step   1   :

1.1     4 = 22

(4)3 = (22)3 = 26

equation at the end of step   1   :

  ((23) • 26)2

step   2   :

equation at the end of step   2   :

  (23 • 26)2

step   3   :

final result :

  218

ya

he answer is x=1x3 because x=1 to x=3