If an exterior Angele of a regular polygon is an integer, what are the possible values of the angle?

Please read the explanied answer below.

Step-by-step explanation:

We also know that a regular polygon has all the angles equal and all sides have the same length.

As we know:

When the number of sides changes, the angle also changes. Therefore, we would get different integers as answer.

For example:

In terms of a triangle:

Exterior angle = 360° ÷ No. of sides

                        = 360° ÷ 3 = 120°

In terms of a rectangle:

Exterior angle = 360° ÷ No. of sides

                        = 360° ÷ 4 = 90°

and in the same way

360° ÷ 5 = 72 °

360° ÷ 6 = 60 °

360° ÷ 8 = 45 °

360° ÷ 9 = 40°

and so on.

I hope it may have solved your query.

i need a picure

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!