The center of a circle and a point on the circle are given. Write the equation of the circle in standard form. center: (2,-5), point on the circle: (-4,-5)

Step-by-step explanation:

The standard form of a circle is given by the equation:

Where (h, k) is the center and r is the radius.

We know that the center is (2, -5). So, we can substitute 2 for h and -5 for k. This yields:

Simplify:

Now, we need to determine r. We know that a point on the circle is (-4, -5). Thus, we can determine r by substituting -4 for x and -5 for y. This yields:

Evaluate:

Evaluate:

Hence, the radius squared is 36.

We do not actually need to solve for r, as we will square it anyways.

We will substitute 36 for r squared. Hence, our equation is:

The radius will thus be 6 units.

i got 10.28 but that rounds up to 10.3

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length