What is the weight of the seawater in an aquarium that is 4.4 ft long, 2.5 ft wide, and 5.3 ft high?

The weight of the sea water in the aquarium is 3827.119 lb

Step-by-step explanation:

We start by calculating the volume of the aquarium

Since it is a cuboid, the volume will be L * B * H

= 4.4 * 2.5 * 5.3 = 58.3 ft^3

Mathematically;

Mass = density * volume

The density of sea water is 63.93 lb/ft^3

Mass = 63,93 * 58.3 = 3,827.119 lb

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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