Simplify each of the expressions below using any combination of the properties above and combining like terms. 3x + 5 + 6x ‐ 2(2 + 6x) 5(3x + 3) 3x + 5 − 6x + 16 x 2 y + 2xy 2+ 3x 2 y − 6xy 2+ 4 ‐ 2(2 + 6x) − 5(3x + 3) 8(‐14w + 10) ‐19(10 + 4q) − 13q 4n ‐ 3( ‐9n + 13) ‐19 ‐ 7( ‐17z + 13)

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

answer: correct

step-by-step explanation:

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