Miguel has a total of 27 dimes and nickels. The total value of the coins is $1.80. How many dimes and nickels does he have?

There are 9 dimes and 18 nickels.

Step-by-step explanation:

Let d = be the number of dimes

     n = be the number of nickels

    d + n = 27...eq.1

   0.10d + 0.05n = 1.80...eq.2

Solve the system of equations

   d + n = 27

10d + 5n = 180  ( multiply eq.2 by 100 )

 -5d - 5n = -135

      5d = 45

        d = 9 , there are 9 dimes so,0.90

        n = 27 - 9 = 18,   there are 18 nickels so, 0.90

To check:   9 dimes + 18 nickels = 27 coins

                0.90 + 0.90 = $ 1.80 total value of the coins

the amount you'd have after the work is $1.55

step-by-step explanation:

you subtract 95% from $31.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.