(Ignore the C that was answered I don’t think it’s correct) Angelo wants to graph the quadratic function shown.

c is actually correct lol

Step-by-step explanation:

g(x) = (x-4)(x+2)

set both (x-4) and (x+2) equal to zero

x-4=0

x=4

& bx+2=0

x=-2

c has 4 and -2 as x values

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )