How many real solutions does x²+8x+20=0 have?

Since the solution is a complex value, hence the equation has no real solutions

Givne the quadratic expression x²+8x+20 = 0

Factorizing the function

x²+8x+20 = 0

x = -8±√8²-4(20)/2

x = -8±√64-80/2

x = -8±√-16/2

x = -8±4i/2

x = -4±2i

Since the solution is a complex value, hence the equation has no real solutions

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No real solutions

Step-by-step explanation:

Use the discriminant formula, D = b² - 4ac

D = b² - 4ac

Plug in b, a, and c:

D = b² - 4ac

D = (8)² - 4(1)(20)

D = 64 - 80

D = -16

Since the discriminant is negative, there are no real solutions

answer for #1 is c

answer for #2 is d

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