A plane traveled 336 miles to Carson City and back. The trip there was with the wind. It took 4 hours. The trip back was into the wind. The trip back took 6 hours. What is the speed of the plane in still air? What is the speed of the wind?

Thus, train speed = 70 mph while wind speed is. y = 14 mph

Step-by-step explanation:

Let x = speed of the plane in mph.

Let y = speed of wind in mph.

We are told that The trip there was with the wind. It took 4 hours. The trip back was into the wind. The trip back took 6 hours.

Formula for distance is;

Distance = speed × time

Thus;

(x + y)4 = 336

(x + y) = 84 - - - - (1)

Also;

(x - y)6 = 336

Divide both sides by 6

(x - y) = 56 - - - (eq 2)

Add eq 1 and 2 to give;

2x = 84 + 56

2x = 140

x = 140/2

x = 70 mph

Plug in 70 mAh for x in eq 1.

(70 - y) = 56

y = 70 - 56

y = 14 mph

Thus, train speed = 70 mAh while wind speed is. y = 14 mph

12 servings. 4 times 3= 12

idk

step-by-step explanation:

do it yourself, cause that made me do it myself today, in english!