How do you do this question?

(a) >, decreasing

(b) 0, horizontal

Step-by-step explanation:

(a) dy/dt = eᵗ (y − 1)²

eᵗ is always positive, and (y − 1)² is always positive.  So dy/dt is always positive.  Meaning the graph of the solution can never be decreasing.

(b) When y = 1, dy/dt = e¹ (1 − 1)² = 0.  However, this graph does not have a horizontal tangent line at y=1, so this is not the solution of the differential equation.

ιт ιѕ 6/23

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ!