What is the equation of a line that passes through (-7, 3) and is perpendicular to -5/3x = 1/4y -8 Select all answers that apply
Y = 3/20x + 81/20
Y-3 = 3/20(x+7)
Y-3 = -20/3(x+7)
Y = -20/3x -32
3x -20y = -81
The answer can be anything thing that occurs during solving the problem or is the answer.

The 1st, 2nd and 5th options are correct.

Step-by-step explanation:

The equation of a line can be written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

①Rewrite the given equation into the form of y=mx+c to find the gradient.

Thus, the gradient of the given equation is .

② Find gradient of unknown line.

The product of the gradients of perpendicular lines is -1.

Let m be the gradient of the unknown line.

③Substitute the value of m into the equation.

④ Find the value of c by substituting a pair of coordinates.

When x= -7, y= 3,

Thus, the equation of the line is .

Thus, the 4th option is incorrect.

Writing c as an improper fraction,

Thus, the 1st option is correct.

-3 from both sides of the equation:

Factorise 3/20 out of the right hand side:

Thus, the 2nd option is correct.

The 3rd option is incorrect as factorising -20/3 out would leave us with -0.0225 as the coefficient of x.

Let's look at the 5th option.

×20 on both sides:

-20y on both sides:

-81 on both sides:

Thus, the 5th option is also correct.

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